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Design guide

Column slenderness to Eurocode 2: effective length, slenderness limit and nominal curvature

A slender braced column to EN 1992-1-1, worked step by step: effective length, slenderness and its limit, imperfections, and the nominal curvature method.

Open the column calculator

A slender reinforced concrete column rising through an open building frame
Reading time
4 minutes
Standard
EN 1992-1-1
Clauses
5.2, 5.8.3, 5.8.8
Calculator
Column
Updated
On this page 8 sections
  1. Step 1: Effective length
  2. Step 2: Slenderness
  3. Step 3: The slenderness limit
  4. Step 4: Imperfections
  5. Step 5: The second order moment by nominal curvature
  6. Step 6: The design moment
  7. Step 7: The section
  8. Points to remember

A column that is long for its size bends sideways under its own axial load, and that sideways deflection adds a moment: the second order effect. EN 1992-1-1 decides whether a column is slender by comparing its slenderness with a limit , and, if it is, adds the extra moment, most simply by the nominal curvature method of 5.8.8.

This guide works through the calculator's slender example: a 300 × 300 mm braced column, 6000 mm high between floors, carrying 900 kN with equal end moments of 40 kNm about z.

The answer, worked out below

Slenderness
58.5
λ about z, with l0 = 5069 mm
Limit
19.7
λlim from Expression 5.13N: the column is slender
Second order moment
44.09 kNm
M2 by nominal curvature
Design moment
93.41 kNm
MEd about z, against MRd = 128.54 kNm

The steps below follow this path, once for each axis:

Is the column slender, and what moment does it get?
  1. Effective length l0 from the end restraints (5.15)
  2. Slenderness λ = l0 / i
  3. Limit λlim = 20 A B C / √n (5.13N)
  4. Is λ ≤ λlim?

    Yes

    1. Not slender: first order moments with the imperfection

    No

    1. Slender: add the second order moment
    2. Curvature 1/r = Kr Kφ / r0, deflection e2 = (1/r) l0² / c
    3. MEd = max(M02; M0e + M2; NEd e0)
  5. Check NEd with MEd on the N–M interaction curve
  6. Biaxial bending, if both axes carry moment (5.39)

Step 1: Effective length

The effective length is the length of a pin-ended column with the same buckling load. For a braced column it follows from the restraint at each end (Expression 5.15):

where and are the relative flexibilities of the restraints at the two ends: 0 for full fixity (giving ) and infinity for a pin (giving ). This example takes , a fairly flexible restraint.

EN 1992-1-1 §5.8.3.2(3), Eq. (5.15)

Effective length about z (braced)

k = (θ/M)(EI/l) is the relative flexibility of the end restraint (0 rigid, ∞ pinned); 0.1 is the smallest value used.

= 5069 mm
Effective length about zBraced: the ends do not move sideways.k₂k₁l = 6000l₀ = 5069l₀ is the length of the pin-ended column with the same buckling load (5.8.1).
Effective length about z. The buckled shape between the end restraints; l₀ is the length of the equivalent pin-ended column.

Step 2: Slenderness

The slenderness ratio is the effective length divided by the radius of gyration of the concrete section, for a rectangle bending across :

EN 1992-1-1 §5.8.3.2(1)

Radius of gyration about z

Uncracked concrete section; h is the depth in this direction.

= 86.6 mm
EN 1992-1-1 §5.8.3.2(1), Eq. (5.14)

Slenderness about z

= 58.5

Step 3: The slenderness limit

A column needs no second order moment if , where (Expression 5.13N)

  • allows for creep, through the effective creep ratio ;
  • allows for the steel, with ;
  • allows for the shape of the moment diagram, with .

The moment ratio matters most. Equal moments in single curvature () give ; equal and opposite moments () give , almost four times the limit. This column has equal moments, the worst case:

EN 1992-1-1 §5.8.3.1(1), Eq. (5.13N)

Moment ratio about z

= 1.000
EN 1992-1-1 §5.8.4(2), Eq. (5.19)

Effective creep ratio

M0Eqp/M0Ed is the ratio of the quasi-permanent to the design first order moment, entered with the actions.

= 1.73
EN 1992-1-1 §5.8.3.1(1), Eq. (5.13N)

Slenderness limit about z

ω from the bars provided; rm = M₀₁/M₀₂ with the first order end moments (positive when both give tension on the same side).

= 19.7
EN 1992-1-1 §5.8.3.1(1)
EN 1992-1-1 §5.8.2(6)

Second order effects about z

The column is slender in this direction: the second order moment is added (5.8.8).

The limit falls as the axial force rises, and the moment ratio moves it a long way. Here is Expression 5.13N worked by the calculator for this column's creep and steel, for the three classic moment shapes, with its own slenderness drawn across:

Slenderness limit against the axial force

λlim = 20·A·B·C/√n for a braced column with φef = 1.73 and ω = 0.558, as in the worked example. A column whose λ lies above its curve is slender and needs second order moments.

  • rm = 1, equal end moments
  • rm = 0, one end moment
  • rm = −1, double curvature
0 50 100 150 λlim 0.2 0.4 0.6 0.8 1.0 Relative axial force n Worked column: λ = 58.5 rm = 1, equal end moments rm = 0, one end moment rm = −1, double curvature λlim = 19.7 0 50 100 150 λlim 0.2 0.4 0.6 0.8 1.0 Relative axial force n Worked column: λ = 58.5 λlim = 19.7
Show the numbers
Relative axial force nrm = 1, equal end momentsrm = 0, one end momentrm = −1, double curvature
0.2033.882.2130.5
0.3027.667.1106.5
0.4023.958.192.3
0.5021.452.082.5
0.6019.547.475.3
0.7018.143.969.7
0.8016.941.165.2
0.9015.938.761.5
1.0015.136.758.3

With equal end moments this column is slender over the whole range drawn; in double curvature the same column would not be slender until reached about 1.

Column reinforcement cages standing up from a floor slab before their formwork goes on
Column cages stand on the slab before the formwork goes on. Their links hold the bars in line; the imperfection of 5.2 allows for the column still being slightly out of plumb.

Step 4: Imperfections

Every real column is a little out of line. Clause 5.2 allows for it with an inclination , reduced for taller members by , which for an isolated member becomes an eccentricity , added to the end moments:

EN 1992-1-1 §5.2(5), Eq. (5.1)

Inclination of the imperfection

= 0.00408 rad
EN 1992-1-1 §5.2(7), Eq. (5.2)

Eccentricity for imperfections about z

= 10.3 mm
EN 1992-1-1 §5.8.8.2(1), Eq. (5.31)
EN 1992-1-1 §5.2(7)

Larger first order end moment about z, with the imperfection

First order effects include the geometric imperfections (5.8.1), so NEd·ei is added to the end moments in the direction that increases the larger one.

= 49.31 kNm
EN 1992-1-1 §5.8.8.2(2)

Smaller first order end moment about z, with the imperfection

M₀₁ has the same sign as M₀₂ when both give tension on the same side (single curvature), and the opposite sign in double curvature.

= 49.31 kNm

Step 5: The second order moment by nominal curvature

The nominal curvature method estimates the deflection at mid-height from the curvature at which the steel yields, reduced or increased for the actual axial load and for creep:

  • falls as the axial load rises, because a highly loaded section fails by crushing before the steel yields;
  • increases the curvature for creep;
  • (close to ) for a column of constant section.
EN 1992-1-1 §5.8.8.3(1), Eq. (5.34)

Basic curvature about z

d in metres, so the curvature is per metre.

= 0.01913 1/m
EN 1992-1-1 §5.8.8.3(3), Eq. (5.36)

Correction factor for axial load

nbal = 0.4, the value of n at the largest moment resistance that 5.8.8.3(3) allows.

= 0.837
EN 1992-1-1 §5.8.8.3(4), Eq. (5.37)

Factor for creep

= 1.190
EN 1992-1-1 §5.8.8.3(1), Eq. (5.34)

Curvature about z

= 0.01907 1/m
EN 1992-1-1 §5.8.8.2(3), Eq. (5.33)
EN 1992-1-1 §5.8.8.2(4)

Second order deflection about z

c = 10 (≈ π²) for a constant cross-section; 1/r is divided by 1000 to work in millimetres.

= 49.0 mm
EN 1992-1-1 §5.8.8.2(3), Eq. (5.33)

Nominal second order moment about z

= 44.09 kNm

Step 6: The design moment

For a braced column, the second order moment is largest near mid-height, where the first order moment is replaced by the equivalent moment (Expression 5.32). The design moment is the largest of , and the minimum :

EN 1992-1-1 §5.8.8.2(2), Eq. (5.32)

Equivalent first order moment about z

M0e acts at mid-height, where the second order moment is largest; the end moments alone act at the braced ends.

= 49.31 kNm
EN 1992-1-1 §5.8.8.2(1), Eq. (5.31)
EN 1992-1-1 §6.1(4)

Design moment about z

The mid-height moment M0e + M2 governs.

= 93.41 kNm
Moments along the column about zBraced, slender: M₂ added.M₀₂ = 49.3M₀₁ = 49.3M₀ₑ + M₂ = 93.4first order, with eiwith the second order momentMEd = 93.41 kNm (at mid-height); kNm, drawn to scale.
Moments along the column about z. First order moments with the imperfection NEd·ei (blue) and, for a slender column, with the nominal second order moment M₂ (green).

The second order moment nearly doubles the design moment, from 49.31 kNm to 93.41 kNm.

Step 7: The section

Finally the section is checked for with on its N–M interaction curve:

EN 1992-1-1 §6.1(2)P

Steel needed for bending about z

The bars of the chosen arrangement scaled until MRd = MEd at NEd (the same calculation as the next step).

= 1076 mm² ✓ OK
EN 1992-1-1 §6.1(2)P
EN 1992-1-1 §3.1.7(3)
EN 1992-1-1 §6.1(6), Figure 6.1

Moment resistance about z at NEd

Strain compatibility (6.1): x is found so that the section carries NEd; the stress block s = min(λx; h) with λ = 0.8, η = 1.0, and each bar at Esε ≤ fyd at its depth ai.

= 128.54 kNm ✓ OK
N–M interaction about zSection resistance by strain compatibility (6.1), bars as provided; depth 300 mm.010002000050100150M (kNm)N (kN)NEd = 900MRd,z = 128.5MEd,z = 93.4green: resistanceblue: design point
N–M interaction about z. Every pair (M, N) inside the green line is carried by the section; MRd is read at NEd.

Points to remember

Very slender columns, with above about 100, are usually better made stockier than pushed through the method. The column calculator guide covers the inputs, including unbraced columns and biaxial bending.

Open the column calculator, set the height to 6000 mm and watch the second order moment appear.